3.24.82 \(\int \frac {(2+3 x)^2 \sqrt {3+5 x}}{(1-2 x)^{3/2}} \, dx\)

Optimal. Leaf size=94 \[ \frac {9}{40} \sqrt {1-2 x} (5 x+3)^{3/2}+\frac {49 (5 x+3)^{3/2}}{22 \sqrt {1-2 x}}+\frac {17951 \sqrt {1-2 x} \sqrt {5 x+3}}{1760}-\frac {17951 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{160 \sqrt {10}} \]

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Rubi [A]  time = 0.02, antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {89, 80, 50, 54, 216} \begin {gather*} \frac {9}{40} \sqrt {1-2 x} (5 x+3)^{3/2}+\frac {49 (5 x+3)^{3/2}}{22 \sqrt {1-2 x}}+\frac {17951 \sqrt {1-2 x} \sqrt {5 x+3}}{1760}-\frac {17951 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {5 x+3}\right )}{160 \sqrt {10}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((2 + 3*x)^2*Sqrt[3 + 5*x])/(1 - 2*x)^(3/2),x]

[Out]

(17951*Sqrt[1 - 2*x]*Sqrt[3 + 5*x])/1760 + (49*(3 + 5*x)^(3/2))/(22*Sqrt[1 - 2*x]) + (9*Sqrt[1 - 2*x]*(3 + 5*x
)^(3/2))/40 - (17951*ArcSin[Sqrt[2/11]*Sqrt[3 + 5*x]])/(160*Sqrt[10])

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 54

Int[1/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_.) + (d_.)*(x_)]), x_Symbol] :> Dist[2/Sqrt[b], Subst[Int[1/Sqrt[b*c -
a*d + d*x^2], x], x, Sqrt[a + b*x]], x] /; FreeQ[{a, b, c, d}, x] && GtQ[b*c - a*d, 0] && GtQ[b, 0]

Rule 80

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[(b*(c + d*x)
^(n + 1)*(e + f*x)^(p + 1))/(d*f*(n + p + 2)), x] + Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1) + c*f*(p + 1)))/(
d*f*(n + p + 2)), Int[(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && NeQ[n + p + 2,
0]

Rule 89

Int[((a_.) + (b_.)*(x_))^2*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((b*c - a*
d)^2*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d^2*(d*e - c*f)*(n + 1)), x] - Dist[1/(d^2*(d*e - c*f)*(n + 1)), In
t[(c + d*x)^(n + 1)*(e + f*x)^p*Simp[a^2*d^2*f*(n + p + 2) + b^2*c*(d*e*(n + 1) + c*f*(p + 1)) - 2*a*b*d*(d*e*
(n + 1) + c*f*(p + 1)) - b^2*d*(d*e - c*f)*(n + 1)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, p}, x] && (LtQ
[n, -1] || (EqQ[n + p + 3, 0] && NeQ[n, -1] && (SumSimplerQ[n, 1] ||  !SumSimplerQ[p, 1])))

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rubi steps

\begin {align*} \int \frac {(2+3 x)^2 \sqrt {3+5 x}}{(1-2 x)^{3/2}} \, dx &=\frac {49 (3+5 x)^{3/2}}{22 \sqrt {1-2 x}}-\frac {1}{22} \int \frac {\sqrt {3+5 x} \left (\frac {853}{2}+99 x\right )}{\sqrt {1-2 x}} \, dx\\ &=\frac {49 (3+5 x)^{3/2}}{22 \sqrt {1-2 x}}+\frac {9}{40} \sqrt {1-2 x} (3+5 x)^{3/2}-\frac {17951}{880} \int \frac {\sqrt {3+5 x}}{\sqrt {1-2 x}} \, dx\\ &=\frac {17951 \sqrt {1-2 x} \sqrt {3+5 x}}{1760}+\frac {49 (3+5 x)^{3/2}}{22 \sqrt {1-2 x}}+\frac {9}{40} \sqrt {1-2 x} (3+5 x)^{3/2}-\frac {17951}{320} \int \frac {1}{\sqrt {1-2 x} \sqrt {3+5 x}} \, dx\\ &=\frac {17951 \sqrt {1-2 x} \sqrt {3+5 x}}{1760}+\frac {49 (3+5 x)^{3/2}}{22 \sqrt {1-2 x}}+\frac {9}{40} \sqrt {1-2 x} (3+5 x)^{3/2}-\frac {17951 \operatorname {Subst}\left (\int \frac {1}{\sqrt {11-2 x^2}} \, dx,x,\sqrt {3+5 x}\right )}{160 \sqrt {5}}\\ &=\frac {17951 \sqrt {1-2 x} \sqrt {3+5 x}}{1760}+\frac {49 (3+5 x)^{3/2}}{22 \sqrt {1-2 x}}+\frac {9}{40} \sqrt {1-2 x} (3+5 x)^{3/2}-\frac {17951 \sin ^{-1}\left (\sqrt {\frac {2}{11}} \sqrt {3+5 x}\right )}{160 \sqrt {10}}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 78, normalized size = 0.83 \begin {gather*} \frac {-10 \sqrt {2 x-1} \sqrt {5 x+3} \left (360 x^2+1518 x-2809\right )-17951 \sqrt {10} (2 x-1) \sinh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {2 x-1}\right )}{1600 \sqrt {-(1-2 x)^2}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[((2 + 3*x)^2*Sqrt[3 + 5*x])/(1 - 2*x)^(3/2),x]

[Out]

(-10*Sqrt[-1 + 2*x]*Sqrt[3 + 5*x]*(-2809 + 1518*x + 360*x^2) - 17951*Sqrt[10]*(-1 + 2*x)*ArcSinh[Sqrt[5/11]*Sq
rt[-1 + 2*x]])/(1600*Sqrt[-(1 - 2*x)^2])

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IntegrateAlgebraic [A]  time = 0.15, size = 109, normalized size = 1.16 \begin {gather*} \frac {\sqrt {5 x+3} \left (\frac {89755 (1-2 x)^2}{(5 x+3)^2}+\frac {59858 (1-2 x)}{5 x+3}+7840\right )}{160 \sqrt {1-2 x} \left (\frac {5 (1-2 x)}{5 x+3}+2\right )^2}+\frac {17951 \tan ^{-1}\left (\frac {\sqrt {\frac {5}{2}} \sqrt {1-2 x}}{\sqrt {5 x+3}}\right )}{160 \sqrt {10}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((2 + 3*x)^2*Sqrt[3 + 5*x])/(1 - 2*x)^(3/2),x]

[Out]

(Sqrt[3 + 5*x]*(7840 + (89755*(1 - 2*x)^2)/(3 + 5*x)^2 + (59858*(1 - 2*x))/(3 + 5*x)))/(160*Sqrt[1 - 2*x]*(2 +
(5*(1 - 2*x))/(3 + 5*x))^2) + (17951*ArcTan[(Sqrt[5/2]*Sqrt[1 - 2*x])/Sqrt[3 + 5*x]])/(160*Sqrt[10])

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fricas [A]  time = 1.24, size = 81, normalized size = 0.86 \begin {gather*} \frac {17951 \, \sqrt {10} {\left (2 \, x - 1\right )} \arctan \left (\frac {\sqrt {10} {\left (20 \, x + 1\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{20 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) + 20 \, {\left (360 \, x^{2} + 1518 \, x - 2809\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{3200 \, {\left (2 \, x - 1\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^2*(3+5*x)^(1/2)/(1-2*x)^(3/2),x, algorithm="fricas")

[Out]

1/3200*(17951*sqrt(10)*(2*x - 1)*arctan(1/20*sqrt(10)*(20*x + 1)*sqrt(5*x + 3)*sqrt(-2*x + 1)/(10*x^2 + x - 3)
) + 20*(360*x^2 + 1518*x - 2809)*sqrt(5*x + 3)*sqrt(-2*x + 1))/(2*x - 1)

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giac [A]  time = 0.98, size = 71, normalized size = 0.76 \begin {gather*} -\frac {17951}{1600} \, \sqrt {10} \arcsin \left (\frac {1}{11} \, \sqrt {22} \sqrt {5 \, x + 3}\right ) + \frac {{\left (6 \, {\left (12 \, \sqrt {5} {\left (5 \, x + 3\right )} + 181 \, \sqrt {5}\right )} {\left (5 \, x + 3\right )} - 17951 \, \sqrt {5}\right )} \sqrt {5 \, x + 3} \sqrt {-10 \, x + 5}}{4000 \, {\left (2 \, x - 1\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^2*(3+5*x)^(1/2)/(1-2*x)^(3/2),x, algorithm="giac")

[Out]

-17951/1600*sqrt(10)*arcsin(1/11*sqrt(22)*sqrt(5*x + 3)) + 1/4000*(6*(12*sqrt(5)*(5*x + 3) + 181*sqrt(5))*(5*x
+ 3) - 17951*sqrt(5))*sqrt(5*x + 3)*sqrt(-10*x + 5)/(2*x - 1)

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maple [A]  time = 0.01, size = 106, normalized size = 1.13 \begin {gather*} -\frac {\left (-7200 \sqrt {-10 x^{2}-x +3}\, x^{2}+35902 \sqrt {10}\, x \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )-30360 \sqrt {-10 x^{2}-x +3}\, x -17951 \sqrt {10}\, \arcsin \left (\frac {20 x}{11}+\frac {1}{11}\right )+56180 \sqrt {-10 x^{2}-x +3}\right ) \sqrt {-2 x +1}\, \sqrt {5 x +3}}{3200 \left (2 x -1\right ) \sqrt {-10 x^{2}-x +3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x+2)^2*(5*x+3)^(1/2)/(-2*x+1)^(3/2),x)

[Out]

-1/3200*(35902*10^(1/2)*x*arcsin(20/11*x+1/11)-7200*(-10*x^2-x+3)^(1/2)*x^2-17951*10^(1/2)*arcsin(20/11*x+1/11
)-30360*(-10*x^2-x+3)^(1/2)*x+56180*(-10*x^2-x+3)^(1/2))*(-2*x+1)^(1/2)*(5*x+3)^(1/2)/(2*x-1)/(-10*x^2-x+3)^(1
/2)

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maxima [A]  time = 1.17, size = 65, normalized size = 0.69 \begin {gather*} -\frac {17951}{3200} \, \sqrt {5} \sqrt {2} \arcsin \left (\frac {20}{11} \, x + \frac {1}{11}\right ) + \frac {9}{8} \, \sqrt {-10 \, x^{2} - x + 3} x + \frac {849}{160} \, \sqrt {-10 \, x^{2} - x + 3} - \frac {49 \, \sqrt {-10 \, x^{2} - x + 3}}{4 \, {\left (2 \, x - 1\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^2*(3+5*x)^(1/2)/(1-2*x)^(3/2),x, algorithm="maxima")

[Out]

-17951/3200*sqrt(5)*sqrt(2)*arcsin(20/11*x + 1/11) + 9/8*sqrt(-10*x^2 - x + 3)*x + 849/160*sqrt(-10*x^2 - x +
3) - 49/4*sqrt(-10*x^2 - x + 3)/(2*x - 1)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (3\,x+2\right )}^2\,\sqrt {5\,x+3}}{{\left (1-2\,x\right )}^{3/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((3*x + 2)^2*(5*x + 3)^(1/2))/(1 - 2*x)^(3/2),x)

[Out]

int(((3*x + 2)^2*(5*x + 3)^(1/2))/(1 - 2*x)^(3/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (3 x + 2\right )^{2} \sqrt {5 x + 3}}{\left (1 - 2 x\right )^{\frac {3}{2}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**2*(3+5*x)**(1/2)/(1-2*x)**(3/2),x)

[Out]

Integral((3*x + 2)**2*sqrt(5*x + 3)/(1 - 2*x)**(3/2), x)

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